(125/w^2-5w)+5=25/w-5

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Solution for (125/w^2-5w)+5=25/w-5 equation: 



(125/w^2-5w)+5=25/w-5

We move all terms to the left:

(125/w^2-5w)+5-(25/w-5)=0



Domain of the equation: w^2-5w)!=0

w∈R





Domain of the equation: w-5)!=0

w∈R



We get rid of parentheses

125/w^2-5w-25/w+5+5=0

We calculate fractions

We do not support ewpression: w^3

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